If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9x^2/x=3
We move all terms to the left:
9x^2/x-(3)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
9x^2-3*x=0
We add all the numbers together, and all the variables
9x^2-3x=0
a = 9; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·9·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*9}=\frac{0}{18} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*9}=\frac{6}{18} =1/3 $
| 2x+25+12=x+26 | | 3(4p–5)+2=23 | | -22=-5r-7 | | 6x+17=9x+2-17 | | 20(k-9)=140 | | 4(4w+5)/3=5 | | 11=5j-4 | | 2x-5+8x-1(7x-5)-21x=11-24+1x-4(8-1x)+9 | | 2x+5-8x=24 | | 9^2+12^2=c | | -2=2g-8 | | 12-6a=-9a+4 | | 6x-1=4+6 | | (-2)=3x^2+1 | | 0=-4-2a | | 4x+20=4x-10 | | 4+4j=6j+10 | | 1/3(2c-1)=7 | | 5x+18+14-x+8x-30=180 | | 6x-1=4x=6 | | 3/2v=10 | | 10(s-10)=-174 | | 8-2m=-2m+8 | | -2(-6b+1)=34+6b | | 3t+3=-2t+23 | | 2x=10x-2 | | (3x-1)^2=7 | | 1-3f=4-6f | | -4y+16=20 | | -2+2b=2b-2 | | f(-3)=4(-3)–5 | | 2(3s+8)=28 |